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Python Argument Parser | 2022-05-16T17:07:06-04:00 | false |
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For a much better description of argument parsing in Python, please visit https://docs.python.org/3/library/argparse.html.
I'm creating this post because even though it's not too complicated, I keep forgetting how to do argument parsing in Python. I also tricked myself into thinking each time that I already wrote a blog post on this. Let's correct this once and for all and include a quick example!
import argparse
parser = argparse.ArgumentParser(description="Description to show in help")
parser.add_argument("pos_arg1", type=str, help="Required positional argument")
parser.add_argument("--flag1", type=str, help="Optional flag argument")
parser.add_argument("--flag2", type=int, required=True, help="Required flag argument")
parser.add_argument("--flag3", type=int, default=0, help="Optional flag argument \
with default value of 0")
args = vars(parser.parse_args())
Now if you call the program with no arguments you'll get the following message:
usage: testarg.py [-h] [--flag1 FLAG1] --flag2 FLAG2 pos_arg1
testarg.py: error: the following arguments are required: pos_arg1, --flag2
This comes with a built in -h
as well!
usage: testarg.py [-h] [--flag1 FLAG1] --flag2 FLAG2 pos_arg1
Description to show in help
positional arguments:
pos_arg1 Required positional argument
optional arguments:
-h, --help show this help message and exit
--flag1 FLAG1 Optional flag argument
--flag2 FLAG2 Required flag argument
Within the code you can parse the argument names by accessing the args
dictionary.
pos_arg1 = args['pos_arg1']
flag1 = args['flag1']
flag2 = args['flag2']