3.1 KiB
date | draft | math | medium_enabled | medium_post_id | tags | title | ||
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2022-11-12 21:27:42-05:00 | false | false | true | ddffc5b14ef9 |
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Immutable Traversals with Unfold |
Let's consider the following binary tree:
a
/ \
/ \
b d
\
\
c
We can encode this with the following Scala code:
final case class BinNode(
val label: String,
val left: Option[BinNode],
val right: Option[BinNode]
)
// Leaf Nodes
val c_node = BinNode("c", None, None)
val d_node = BinNode("d", None, None)
// Rest of nodes
val b_node = BinNode("b", None, Some(c_node))
val a_node = BinNode("a", Some(b_node), Some(d_node))
For depth first search, an intuitive immutable implementation would be a recursive function.
// Using Preorder traversal
def DFS(node: BinNode): Iterator[BinNode] =
lazy val left_side = node.left.fold(Iterator.empty[BinNode])(DFS)
lazy val right_side = node.right.fold(Iterator.empty[BinNode])(DFS)
Iterator(node) ++ left_side ++ right_side
Let's evaluate this using our example above:
DFS(a_node).toList.map(_.label)
// List(a, b, c, d)
The recursive implementation inherently uses the system stack to keep track of the nodes. This means that the last element gets evaluated in each step. Otherwise called last-in-first-out (LIFO). Breadth first search, however, uses a queue based approach where the first one added to the data structure is the first one considered (FIFO).
To preserve immutability in our code, we can use unfold
. Here our state is the queue of nodes.
def BFS(node: BinNode): Iterator[BinNode] =
Iterator.unfold(List(node))(q =>
if q.isEmpty then
None
else
val crnt_node = q.head
val next_q = q.tail ++ crnt_node.left ++ crnt_node.right
Some(crnt_node, next_q)
)
Evaluating on our example:
BFS(a_node).toList.map(_.label)
// List(a, b, d, c)
We can also use unfold
for the depth first search approach as well. We can replace the list used with a stack.
import scala.collection.mutable.Stack
def DFS2(node: BinNode): Iterator[BinNode] =
Iterator.unfold(Stack(node))(s =>
if s.isEmpty then
None
else
val crnt_node = s.pop()
s.pushAll(crnt_node.right)
s.pushAll(crnt_node.left)
Some(crnt_node, s)
)
Using a stack introduces some mutability. We can use the immutable list data structure instead, as long as we satisfy the LIFO ordering.
def DFS3(node: BinNode): Iterator[BinNode] =
Iterator.unfold(List(node))(s =>
if s.isEmpty then
None
else
val crnt_node = s.last
val next_s = s.init ++ crnt_node.right ++ crnt_node.left
Some(crnt_node, next_s)
)