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date | draft | math | medium_enabled | medium_post_id | tags | title | |
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2022-06-19 18:49:47-04:00 | false | false | true | 8217bfd3af16 |
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Conditional Assignment in Bash |
Many programming languages include an quick way to perform a conditional assignment. That is, assigning a variable with a value based on some condition. Normally this is done through a ternary operator. For example, here is how to write it in Javascript
age = 16;
ageType = (age > 18) "Adult": "Child";
The variable ageType
is dependent upon the value of age
. If it is above 18 then ageType = "Adult"
otherwise ageType = "Child"
.
A more verbose way of accomplishing the same thing is the following:
if (age > 18) {
ageType = "Adult"
} else {
ageType = "Child"
}
How do we do conditional assignment in Bash? One way is to make use of subshells and echoing out the values.
AGE_TYPE=$([ $AGE -gt 18 ] && echo "Adult" || echo "Child")
A common programming feature called short-circuiting makes it
so that if the first condition ([ $AGE -gt 18 ]
) is false, then it
will skip the right side of the AND (&&
) expression. This is because
False && True
is always False
. However, False || True
is equal
to True
, so the language needs to evaluate the right part of an
OR (||
) expression.