mirror of
https://github.com/Brandon-Rozek/website.git
synced 2024-09-19 06:05:14 -04:00
49 lines
No EOL
1.3 KiB
Markdown
49 lines
No EOL
1.3 KiB
Markdown
---
|
|
date: 2021-03-15 23:11:35
|
|
draft: false
|
|
math: true
|
|
medium_enabled: true
|
|
medium_post_id: 2a32b08bd2c1
|
|
tags: []
|
|
title: Human Readable Sizes
|
|
---
|
|
|
|
When playing with large and small values, it is useful to convert them to a different unit in scientific notation. Let's look at bytes.
|
|
|
|
```python
|
|
size_categories = ["B", "KB", "MB", "GB", "TB"]
|
|
```
|
|
|
|
You can figure out how to best represent it by seeing how many of the base (in this case 1000) fits into the value.
|
|
$$
|
|
category = \lfloor \frac{\log{(size_{bytes})}}{\log{(base)}} \rfloor
|
|
$$
|
|
You'll want to make sure that you don't overflow in the number of categories you have
|
|
|
|
```python
|
|
category_num = min(category_num, len(size_categories))
|
|
```
|
|
|
|
You can then get its category representation by
|
|
$$
|
|
size = \frac{size_{bytes}}{(2^{category})}
|
|
$$
|
|
We can wrap this all up info a nice python function
|
|
|
|
```python
|
|
def humanReadableBytes(num_bytes: int) -> str:
|
|
base = 1000
|
|
|
|
# Zero Case
|
|
if num_bytes == 0:
|
|
return "0"
|
|
|
|
size_categories = ["B", "KB", "MB", "GB", "TB"]
|
|
category_num = int(math.log(num_bytes) / math.log(base))
|
|
|
|
# Make sure it doesn't overflow
|
|
category_num = min(category_num, len(size_categories) - 1)
|
|
|
|
return "{:.2f} ".format(num_bytes / (base ** category_num)) + \
|
|
size_categories[category_num]
|
|
``` |