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Typo fix
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@ -38,7 +38,7 @@ $$
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(\forall x \phi) \implies \psi &\iff \neg (\forall x \phi) \vee \psi \tag{0.1} \\\\
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(\forall x \phi) \implies \psi &\iff \neg (\forall x \phi) \vee \psi \tag{0.1} \\\\
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&\iff (\exists x \neg \phi) \vee \psi \tag{2.2}\\\\
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&\iff (\exists x \neg \phi) \vee \psi \tag{2.2}\\\\
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&\iff \exists x (\neg \phi \vee \psi) \tag{2.1}\\\\
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&\iff \exists x (\neg \phi \vee \psi) \tag{2.1}\\\\
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&\iff \exists x (\neg \phi \implies \psi) \tag{0.1}
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&\iff \exists x (\phi \implies \psi) \tag{0.1}
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\end{align*}
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\end{align*}
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$$
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$$
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**2.** Show that $\phi \implies (\exists x \psi)$ is equivalent to $\exists x (\phi \implies \psi)$
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**2.** Show that $\phi \implies (\exists x \psi)$ is equivalent to $\exists x (\phi \implies \psi)$
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