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[kaltura] Fix service URL extraction (closes #22658)

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Sergey M․ 2019-10-10 00:24:03 +07:00
parent 1907f06e7b
commit 07b50f616e
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1 changed files with 4 additions and 4 deletions
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8
youtube_dl/extractor/kaltura.py
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@ -155,11 +155,11 @@ def _extract_url(webpage):
embed_info[k] = v.strip() embed_info[k] = v.strip()
url = 'kaltura:%(partner_id)s:%(id)s' % embed_info url = 'kaltura:%(partner_id)s:%(id)s' % embed_info
escaped_pid = re.escape(embed_info['partner_id']) escaped_pid = re.escape(embed_info['partner_id'])
service_url = re.search( service_mobj = re.search(
r'<script[^>]+src=["\']((?:https?:)?//.+?)/p/%s/sp/%s00/embedIframeJs' % (escaped_pid, escaped_pid), r'<script[^>]+src=(["\'])(?P<id>(?:https?:)?//(?:(?!\1).)+)/p/%s/sp/%s00/embedIframeJs' % (escaped_pid, escaped_pid),
webpage) webpage)
if service_url: if service_mobj:
url = smuggle_url(url, {'service_url': service_url.group(1)}) url = smuggle_url(url, {'service_url': service_mobj.group('id')})
return url return url
def _kaltura_api_call(self, video_id, actions, service_url=None, *args, **kwargs): def _kaltura_api_call(self, video_id, actions, service_url=None, *args, **kwargs):