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Remove redundant field in sort helper struct
The pair struct used by sortSeq() had two key fields, where only one is really needed.
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parent
9c5f2befc0
commit
3392133128
1 changed files with 9 additions and 12 deletions
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@ -1040,10 +1040,9 @@ func sortSeq(seq interface{}, args ...interface{}) (interface{}, error) {
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switch seqv.Kind() {
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case reflect.Array, reflect.Slice:
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for i := 0; i < seqv.Len(); i++ {
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p.Pairs[i].Key = reflect.ValueOf(i)
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p.Pairs[i].Value = seqv.Index(i)
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if sortByField == "" || sortByField == "value" {
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p.Pairs[i].SortByValue = p.Pairs[i].Value
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p.Pairs[i].Key = p.Pairs[i].Value
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} else {
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v := p.Pairs[i].Value
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var err error
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@ -1053,19 +1052,18 @@ func sortSeq(seq interface{}, args ...interface{}) (interface{}, error) {
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return nil, err
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}
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}
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p.Pairs[i].SortByValue = v
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p.Pairs[i].Key = v
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}
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}
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case reflect.Map:
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keys := seqv.MapKeys()
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for i := 0; i < seqv.Len(); i++ {
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p.Pairs[i].Key = keys[i]
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p.Pairs[i].Value = seqv.MapIndex(keys[i])
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if sortByField == "" {
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p.Pairs[i].SortByValue = p.Pairs[i].Key
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p.Pairs[i].Key = keys[i]
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} else if sortByField == "value" {
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p.Pairs[i].SortByValue = p.Pairs[i].Value
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p.Pairs[i].Key = p.Pairs[i].Value
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} else {
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v := p.Pairs[i].Value
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var err error
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@ -1075,7 +1073,7 @@ func sortSeq(seq interface{}, args ...interface{}) (interface{}, error) {
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return nil, err
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}
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}
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p.Pairs[i].SortByValue = v
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p.Pairs[i].Key = v
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}
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}
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}
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@ -1086,9 +1084,8 @@ func sortSeq(seq interface{}, args ...interface{}) (interface{}, error) {
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// https://groups.google.com/forum/#!topic/golang-nuts/FT7cjmcL7gw
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// A data structure to hold a key/value pair.
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type pair struct {
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Key reflect.Value
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Value reflect.Value
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SortByValue reflect.Value
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Key reflect.Value
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Value reflect.Value
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}
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// A slice of pairs that implements sort.Interface to sort by Value.
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@ -1101,8 +1098,8 @@ type pairList struct {
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func (p pairList) Swap(i, j int) { p.Pairs[i], p.Pairs[j] = p.Pairs[j], p.Pairs[i] }
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func (p pairList) Len() int { return len(p.Pairs) }
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func (p pairList) Less(i, j int) bool {
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iv := p.Pairs[i].SortByValue
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jv := p.Pairs[j].SortByValue
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iv := p.Pairs[i].Key
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jv := p.Pairs[j].Key
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if iv.IsValid() {
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if jv.IsValid() {
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