From 46ba407a7af1323a1a32e691826319917ab08ffd Mon Sep 17 00:00:00 2001 From: Brandon Rozek Date: Tue, 29 Oct 2024 14:14:03 -0400 Subject: [PATCH] New Post --- .../blog/intro-dempster-shafer-possibility.md | 120 ++++++++++++++++++ 1 file changed, 120 insertions(+) create mode 100644 content/blog/intro-dempster-shafer-possibility.md diff --git a/content/blog/intro-dempster-shafer-possibility.md b/content/blog/intro-dempster-shafer-possibility.md new file mode 100644 index 0000000..6edf5bc --- /dev/null +++ b/content/blog/intro-dempster-shafer-possibility.md @@ -0,0 +1,120 @@ +--- +title: "Introduction to Dempster-Shafer Theory" +date: 2024-10-29T12:38:21-04:00 +draft: false +tags: [] +math: true +medium_enabled: false +--- + +Imagine sitting by a tree full of birds. You know the tree only has a Yellow Rumped Warbler ($w$), a Northern Cardinal ($c$), and an American Goldfinch ($g$). These birds are respectful in that they don't call at the same time. + +You make the following observations of bird calls: +$$ +obs = w, w, c, g, g, w +$$ +What's the probability that we hear a Warbler next assuming the calls are independent from each other? +$$ +count_w = 3, total = 6, P(w) = \frac{3}{6} = 0.5 +$$ +This example assumes that we're bird call experts and are able to uniquely determine each bird call. What happens if our observations are *imprecise*? + +## Dempster-Shafer Theory (DST) + +DST, otherwise known as belief functions theory or the theory of evidence, looks at what happens if we allow each observation to be a disjunction ($\vee$)? +$$ +obs = w \vee c \vee g, c, w \vee c, w \vee g +$$ +There can be many reasons for this. Maybe our hearing isn't so good. There's additional noise around you disrupting your sensing. + +Formally, let us define $\Omega$ to be our event space. In this example, this is the set of possible bird calls. +$$ +\Omega = \\{w, c, g\\} +$$ +**The mass function** $m: A \rightarrow [0, 1], \forall A \subseteq \Omega$ assigns a value between 0 and 1 to every possible subset of our event space. The set $\\{w, g\\}$ represents the observation $w \vee g$. + +An important property is that the sum of all the masses are equal to 1. +$$ +\sum_{A \subseteq \Omega} m(A) = 1 +$$ +In order to derive this mass function, we can normalize our observations from earlier. +$$ +m(\\{w, c, g\\}) = \frac{1}{4}, m(\\{c\\}) = \frac{1}{4}, m(\\{w, c\\}) = \frac{1}{4}, m(\\{w, g\\}) = \frac{1}{4} +$$ +We assign the value $0$ to all other subsets of $\Omega$. By definition, $m(\\{\\}) = 0$. + +**The plausibility measure** for a disjunctive set $A$ is the sum of all the mass values of the subets of $\Omega$ that intersect with $A$. +$$ +Pl(A) = \sum_{B \cap A \ne \emptyset}{m(B)} +$$ +In our example, +$$ +\begin{align*} +Pl(\\{w\\}) &= m(\\{w, c, g\\}) + m(\\{w, c\\}) + m(\\{w,g\\}) + m(\\{w\\}) \\\\ + &= \frac{3}{4} +\end{align*} +$$ +**The necessity measure** is more restrictive in that we only look at the summation of the masses of the subsets of $A$. +$$ +Nec(A) = \sum_{B \subseteq A}{m(B)} +$$ +Consider an arbitrary event $a \in \Omega$. Then, +$$ +\begin{align*} +Nec(\\{a\\}) &= m(\\{a\\}) + m(\\{\\}) \\\\ + &= m(\\{a\\}) +\end{align*} +$$ +Therefore in our example, +$$ +Nec(\\{w\\}) = 0, Nec(\\{c\\}) = \frac{1}{4}, Nec(\\{g\\}) = 0 +$$ +Another example, +$$ +\begin{align*} +Nec(\\{w, c\\}) &= m(\\{w, c\\}) + m(\\{c\\}) + m(\\{w\\}) + m(\\{\\}) \\\\ + &= \frac{1}{4} + \frac{1}{4} + 0 + 0 \\\ + &= 0.5 +\end{align*} +$$ +**The probability measure** is bounded by the necessity and plausibility measures. + +For a disjunctive set $A$, +$$ +Nec(A) \le P(A) \le Pl(A) +$$ +Extending probability to a range of values gives us a way to model *ignorance*. We say an agent is completely ignorant if $|\Omega| > 1$ and $m(\Omega) = 1$. + +Consider a completely ignorant agent where $\Omega = \\{w, c, g\\}$. + +Then, +$$ +\begin{align*} +Nec(\\{w\\}) \le P(\\{w\\}) &\le Pl(\\{w\\}) \\\\ +m(\\{w\\}) \le P(\\{w\\}) &\le m(\\{w\\}) + m(\\{w, c\\}) + m(\\{w, g\\}) + m(\\{w, c, g\\}) \\\\ +0 \le P(\\{w\\}) &\le 1 +\end{align*} +$$ +Probability theory is a subset of Dempster-Shafer theory. In order to see this, let us look at an example of observations where there is no disjunction. +$$ +obs = w, w, c, g, g, w +$$ +Normalize our observations to derive the mass function: +$$ +m(\\{w\\}) = \frac{1}{2}, m(\\{c\\}) = \frac{1}{6}, m(\\{g\\}) = \frac{1}{3} +$$ +The mass function in this example is $0$ for every non-singleton subset of $\Omega$. + +What is the probability range for $w$? +$$ +\begin{align*} +Nec(\\{w\\}) \le P(\\{w\\}) &\le Pl(\\{w\\}) \\\\ +m(\\{w\\}) \le P(\\{w\\}) &\le m(\\{w\\}) + m(\\{w, g\\}) + m(\\{w, c\\}) + m(\\{w, c, g\\}) \\\\ +\frac{1}{2} \le P(\\{w\\}) &\le \frac{1}{2} + 0 + 0 + 0 +\end{align*} +$$ +Therefore, $P(w) = \frac{1}{2}$ as expected in probability theory. + +## Conclusion + +Dempster-Shafer theory is an attempt at addressing *imprecise observations* through disjunctive events. It extends probability theory to consider not just a single value, but a range of possible values. This allows the model to decouple uncertainty from *ignorance*.